400/x^2=300(20-x)^2

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Solution for 400/x^2=300(20-x)^2 equation: 



400/x^2=300(20-x)^2

We move all terms to the left:

400/x^2-(300(20-x)^2)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

400/x^2-(300(-1x+20)^2)=0

We multiply all the terms by the denominator


-((300(-1x+20)^2))*x^2+400=0

We move all terms containing x to the left, all other terms to the right

-((300(-1x+20)^2))*x^2=-400

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